A) \[RC{{H}_{2}}-COCl\]
B) \[RC{{H}_{2}}-COOH\]
C) \[RCOCN\]
D) \[RCN\]
E) \[R-OH\]
Correct Answer: B
Solution :
\[R\,COOH+PC{{l}_{5}}\to R\,COCl+POC{{l}_{3}}+HCl\xrightarrow{KCN}\] \[R\,COCN+KCl\xrightarrow{2\,{{H}_{2}}O}R\,CO\,COOH+2N{{H}_{3}}\] \[\underset{Zn-Hg/Conc.\ \,HCl}{\mathop{\xrightarrow{Clemenson\ reduction}}}\,R\,C{{H}_{2}}COOH+{{H}_{2}}O\]
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