A) \[PC{{l}_{5}}\]
B) \[C{{l}_{2}}\]
C) \[SOC{{l}_{2}}\]
D) \[PC{{l}_{3}}\]
Correct Answer: B
Solution :
\[C{{H}_{3}}COOH+C{{l}_{2}}\to C{{H}_{2}}Cl\,COOH+HCl\] \[C{{H}_{3}}COOH+PC{{l}_{5}}\to C{{H}_{3}}COCl+POC{{l}_{3}}+HCl\] \[C{{H}_{3}}COOH+SOC{{l}_{2}}\to C{{H}_{3}}COCl+S{{O}_{2}}+HCl\] \[3C{{H}_{3}}COOH+PC{{l}_{3}}\to 3C{{H}_{3}}COCl+{{H}_{3}}P{{O}_{3}}\]
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