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JEE Main & Advanced Chemistry Carboxylic Acids Question Bank Properties of Carboxylic Acids and Their Derivatives

  • question_answer
    When propanamide reacts with \[B{{r}_{2}}\] and \[NaOH\] then which of the following compound is formed [Manipal 2001]

    A)                 Ethyl alcohol      

    B)                 Propyl alcohol

    C)                 Propyl amine    

    D)                 Ethylamine

    Correct Answer: D

    Solution :

        \[\underset{\text{Propionamide}}{\mathop{C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}}}\,\overset{B{{r}_{2}}/KOH}{\mathop{\xrightarrow[\begin{smallmatrix}  \text{Hofmann}\,\text{bromamide} \\  \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{reaction} \end{smallmatrix}]{}}}\,\underset{\text{Ethylamine}}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,\]


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