A) \[{{N}_{2}}\]
B) \[C{{O}_{2}}\]
C) Biurette
D) Ammonium carbonate
Correct Answer: C
Solution :
\[\underset{\text{Ammonium cyanate}}{\mathop{N{{H}_{4}}CNO}}\,\xrightarrow{\Delta }\,\,\,\underset{\text{Urea}}{\mathop{N{{H}_{2}}-CO-N{{H}_{2}}}}\,\] \[\underset{{}}{\mathop{N{{H}_{2}}-CO-N{{H}_{2}}}}\,+\underset{\text{Urea}}{\mathop{H-NH-CO-N{{H}_{2}}}}\,\underset{-N{{H}_{3}}}{\mathop{\xrightarrow{\Delta }}}\,\] \[\underset{\text{Biuret}}{\mathop{N{{H}_{2}}-CO-NH-CO-N{{H}_{2}}}}\,\]
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