question_answer

\[C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow{C{{l}_{2}}/Fe}X\underset{K{{O}_{4}}}{\mathop{\xrightarrow{Alcoholic}}}\,Y\] Compound Y is  [DPMT 1981; JIPMER 2000; AIEEE 2002]

A)                 \[C{{H}_{3}}C{{H}_{2}}OH\]        

B)                 \[C{{H}_{3}}C{{H}_{2}}CN\]

C)                 \[C{{H}_{2}}=CHCOOH\]              

D)                 \[C{{H}_{3}}CHClCOOH\]

Correct Answer: C

Solution :