A) Ethyl benzoate
B) Ethyl formate
C) Ethyl acetate
D) Methyl acetate
Correct Answer: A
Solution :
\[{{C}_{6}}{{H}_{5}}COO{{C}_{2}}{{H}_{5}}+KOH\,(alc)\to {{C}_{6}}{{H}_{5}}COOK+\] \[{{C}_{2}}{{H}_{5}}OH\xrightarrow{HCl}{{C}_{6}}{{H}_{5}}COOH+KCl\]You need to login to perform this action.
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