A) Acetic acid
B) Propionic acid
C) Acrylic acid
D) Formic acid
Correct Answer: C
Solution :
\[C{{H}_{3}}-\underset{OH}{\mathop{\underset{|\,\,\,\,\,}{\mathop{CH}}\,}}\,-COOH\xrightarrow{{{H}_{2}}S{{O}_{4}}}\underset{\text{Acrylic}\,\,\text{acid}}{\mathop{C{{H}_{2}}=CH-COOH}}\,\]You need to login to perform this action.
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