A) \[NaB{{H}_{4}}\]
B) \[{{H}_{2}}-Pd/C\]
C) \[LiAl{{H}_{4}}\]
D) \[Zn-Hg/HCl\]
Correct Answer: D
Solution :
C6H5CONHCH3 \[\underset{HCl}{\mathop{\xrightarrow{Zn-Hg/}}}\,\]C6H5CH2NHCH3 This reaction is known as Clemmenson reduction.You need to login to perform this action.
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