A) Ethyl alcohol
B) Propyl alcohol
C) Propyl amine
D) Ethylamine
Correct Answer: D
Solution :
\[\underset{\text{Propionamide}}{\mathop{C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}}}\,\overset{B{{r}_{2}}/KOH}{\mathop{\xrightarrow[\begin{smallmatrix} \text{Hofmann}\,\text{bromamide} \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{reaction} \end{smallmatrix}]{}}}\,\underset{\text{Ethylamine}}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,\]You need to login to perform this action.
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