A) \[C{{H}_{4}}\]
B) \[C{{H}_{3}}OH\]
C) Acetonitrile
D) Ammonium acetate
Correct Answer: C
Solution :
\[C{{H}_{3}}COOH\xrightarrow{N{{H}_{3}}}C{{H}_{3}}CON{{H}_{2}}\underset{{{P}_{2}}{{O}_{5}}}{\mathop{\xrightarrow{\Delta }}}\,C{{H}_{3}}-C\equiv N\]You need to login to perform this action.
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