A) Benzyl alcohol and ethanoic acid
B) Sodium benzoate and ethanol
C) Benzoic acid and sodium ethoxide
D) Phenol and ethanoic acid
E) Sodium benzoxide and ethanoic acid
Correct Answer: B
Solution :
\[\underset{\text{Ethyl}\,\text{benzoate}}{\mathop{{{C}_{6}}{{H}_{5}}COO{{C}_{2}}{{H}_{5}}}}\,+NaOH\xrightarrow{\Delta }\]\[\underset{\text{Sod}\text{.}\,\text{benzoate}}{\mathop{{{C}_{6}}{{H}_{5}}COONa}}\,+\underset{\text{Ethanol}}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,\]
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