A) 2
B) 1
C) 0
D) \[\pi \]
Correct Answer: C
Solution :
If\[f(x)=\log \left( \frac{1+x}{1-x} \right)\,,\]then\[f(-x)=\log \left( \frac{1-x}{1+x} \right)=-f(x)\] Therefore, \[\int_{-1}^{1}{\log \left( \frac{1+x}{1-x} \right)\text{ }dx=0}\].You need to login to perform this action.
You will be redirected in
3 sec