A) 0
B) 1
C) \[-1\]
D) None of these
Correct Answer: A
Solution :
Let \[f(x)=\sqrt{1+x+{{x}^{2}}}-\sqrt{1-x+{{x}^{2}}}\]. Then \[f(-x)=\sqrt{1-x+{{x}^{2}}}-\sqrt{1+x+{{x}^{2}}}=-f(x)\] Hence \[f(x)\] is an odd function and so \[\int_{-1}^{1}{f(x)dx=0}\].You need to login to perform this action.
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