A) 5/3
B) 7/3
C) 8/3
D) 4/3
Correct Answer: B
Solution :
\[\int_{0}^{2}{{{x}^{2}}[x]dx=\int_{0}^{1}{{{x}^{2}}(0)dx+\int_{1}^{2}{{{x}^{2}}(1)dx=0+\left[ \frac{{{x}^{3}}}{3} \right]}_{1}^{2}=\frac{7}{3}}}\].You need to login to perform this action.
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