A) \[2{{e}^{-1}}\]
B) 1
C) 0
D) None of these
Correct Answer: C
Solution :
\[I=\int_{-\pi /2}^{\pi /2}{\frac{\sin x}{1+{{\cos }^{2}}x}{{e}^{-{{\cos }^{2}}x}}dx}\] \[\because \frac{\sin x}{1+{{\cos }^{2}}x}{{e}^{-{{\cos }^{2}}x}}\]is an odd function, \\[I=0\].You need to login to perform this action.
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