A) 0
B) 1
C) 2
D) 3
Correct Answer: C
Solution :
\[\int_{-2}^{3}{f(x)\,dx=}\int_{-2}^{2}{f(x)\,dx+\int_{2}^{3}{\,f(x)\,dx}}\] \[\because \] \[{{e}^{\cos x}}\sin x\]is an odd function \[\therefore \,\int_{-2}^{3}{f(x)\,dx}=\int_{-2}^{2}{{{e}^{\cos x}}\sin x\,dx+\int_{2}^{3}{2\,dx=0+2\,(3-2)=2}}\].You need to login to perform this action.
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