A) 1
B) 2
C) \[\frac{\pi }{4}\]
D) 0
Correct Answer: D
Solution :
\[I=\int_{0}^{2\pi }{\frac{\sin 2\theta }{a-b\cos \theta }d\theta =\int_{0}^{2\pi }{\frac{\sin (2\pi -2\theta )}{a-b\cos (2\pi -\theta )}d\theta }}\] Þ I \[=-\int_{0}^{2\pi }{\frac{\sin 2\theta }{a-b\cos \theta }d\theta }\] \[\Rightarrow \,\,2I=0\Rightarrow \,\,\int_{0}^{2\pi }{\frac{\sin 2\theta }{a-b\cos \theta }d\theta =0}\].You need to login to perform this action.
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