A) 1
B) 0
C) 2
D) ?2
Correct Answer: A
Solution :
Given \[f(x)=|x-1|\] \ \[\int_{0}^{2}{f(x)dx=\int_{0}^{2}{\text{ }|x-1|dx}}=\int_{0}^{1}{(1-x)dx+\int_{1}^{2}{(x-1)dx}}\] \[=\left[ x-\frac{{{x}^{2}}}{2} \right]_{0}^{1}+\left[ \frac{{{x}^{2}}}{2}-x \right]_{1}^{2}\] \[=\left( 1-\frac{1}{2} \right)+(2-2)-\left( \frac{1}{2}-1 \right)=1\].You need to login to perform this action.
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