A) \[-1\]
B) 2
C) \[1+{{e}^{-1}}\]
D) None of these
Correct Answer: D
Solution :
\[\int_{0}^{1}{dx+\int_{0}^{1}{{{e}^{-{{x}^{2}}}}dx=1+\int_{0}^{1}{{{e}^{-{{x}^{2}}}}dx}}}\], but \[\int_{0}^{1}{{{e}^{-{{x}^{2}}}}}dx\] is not integrable.You need to login to perform this action.
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