A) \[\frac{\pi }{2}\]
B) \[\frac{\pi }{4}\]
C) \[\frac{\pi }{6}\]
D) 1
Correct Answer: B
Solution :
\[\int_{0}^{\pi /2}{\frac{1}{1+\sqrt{\tan x}}dx=\int_{0}^{\pi /2}{\frac{\sqrt{\cos x}}{\sqrt{\cos x}+\sqrt{\sin x}}dx=\frac{\pi }{4}}}\].
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