A) The value of p
B) The value of q
C) The value of r
D) The value of p and q
Correct Answer: C
Solution :
Since \[\log \left( \frac{1+x}{1-x} \right)\]is an odd function \[\therefore \int_{\,-2}^{\,2}{\left\{ p\log \left( \frac{1+x}{1-x} \right)+q\,\log \,{{\left( \frac{1-x}{1+x} \right)}^{-2}}+r \right\}\,dx}\] \[=r\int_{\,-\,2}^{\,2}{\,dx}=4r.\]Hence depends on the value of r.You need to login to perform this action.
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