A) 10
B) \[\frac{5}{6}\]
C) 21
D) 12
Correct Answer: D
Solution :
\[\int_{1}^{5}{(|x-3|+|1-x|)dx}\]\[=\int_{1}^{5}{|x-3|dx+\int_{1}^{5}{|1-x|}\text{ }dx}\] \[=\int_{1}^{3}{-(x-3)dx+\int_{3}^{5}{(x-3)}\,dx+}\int_{1}^{5}{-(1-x)\,}dx\]\[=12\].You need to login to perform this action.
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