A) Wurtz reaction
B) Sandmeyer's reaction
C) Wurtz-fittig reaction
D) Kolbe reaction
Correct Answer: C
Solution :
It is Wurtz fittig reaction \[{{C}_{6}}{{H}_{5}}Br+C{{H}_{3}}Br\underset{\text{Ether}}{\mathop{\xrightarrow{Na}}}\,{{C}_{6}}{{H}_{5}}C{{H}_{3}}+2NaBr\]You need to login to perform this action.
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