A) \[{{C}_{2}}{{H}_{5}}NC\]
B) \[{{C}_{2}}{{H}_{5}}CN\]
C) \[{{H}_{3}}C-NH-C{{H}_{3}}\]
D) \[{{C}_{2}}{{H}_{5}}N{{H}_{2}}\]
Correct Answer: B
Solution :
\[{{C}_{2}}{{H}_{5}}Cl+AgCN\to \underset{\begin{smallmatrix} \text{Ethyl}\,\,\text{isocyanide} \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{(X)} \end{smallmatrix}}{\mathop{{{C}_{2}}{{H}_{5}}-N\vec{=}\,C}}\,+AgCl\] The functional isomer of ethyl isocyanide is ethyl cyanide \[{{C}_{2}}{{H}_{5}}-C\equiv N\].You need to login to perform this action.
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