A) \[C{{H}_{3}}-CH=C{{H}_{2}}\]
B) \[C{{H}_{3}}-C\equiv CH\]
C) \[C{{H}_{3}}C{{H}_{2}}CH(N{{H}_{2}})(Cl)\]
D) \[C{{H}_{3}}C{{H}_{2}}C{{(N{{H}_{2}})}_{2}}\]
Correct Answer: D
Solution :
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