A) Ethane
B) Propane
C) n-butane
D) n-pentane
Correct Answer: C
Solution :
\[{{C}_{2}}{{H}_{5}}Cl+2Na+Cl{{C}_{2}}{{H}_{5}}\underset{\text{Ether}}{\mathop{\xrightarrow{\text{Dry}}}}\,{{C}_{2}}{{H}_{5}}-{{C}_{2}}{{H}_{5}}+2NaCl\]You need to login to perform this action.
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