A) Aniline
B) Benzamide
C) Acetamide
D) Nitrobenzene
Correct Answer: B
Solution :
\[{{C}_{6}}{{H}_{5}}CON{{H}_{2}}+B{{r}_{2}}+KOH\to {{C}_{6}}{{H}_{5}}CONHBr+KBr+{{H}_{2}}O\] \[\downarrow KOH\] \[{{K}_{2}}C{{O}_{3}}+{{C}_{6}}{{H}_{5}}N{{H}_{2}}\xleftarrow[2\,KOH]{}{{C}_{6}}{{H}_{5}}NCO+KBr+{{H}_{2}}O\] \[{{C}_{6}}{{H}_{5}}N{{H}_{2}}+{{(C{{H}_{3}}CO)}_{2}}O\to C{{H}_{3}}\underset{\begin{smallmatrix} Acetanilide\text{ } \\ \left( antipyretic \right) \end{smallmatrix}}{\mathop{CONH{{C}_{6}}{{H}_{5}}}}\,+C{{H}_{3}}COOH\]You need to login to perform this action.
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