A) Ethylamine
B) Methylamine
C) Dimethylamine
D) Trimethylamine
Correct Answer: C
Solution :
\[C{{H}_{3}}NC+4H\underset{\text{ether}}{\mathop{\xrightarrow{LiAl{{H}_{4}}}}}\,{{(C{{H}_{3}})}_{2}}NH\].
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