\[Y+Mg\ (OH)\ Cl\] [Kerala PMT 2003]
A) \[X=MgC{{l}_{2}};\ \ Y=C{{H}_{3}}CH=C{{H}_{2}}\]
B) \[X=C{{H}_{3}}MgCl;\ Y={{C}_{2}}{{H}_{5}}COC{{H}_{3}}\]
C) \[X=C{{H}_{3}}MgCl;\ Y={{(C{{H}_{3}})}_{3}}\ C-OH\]
D) \[X={{C}_{2}}{{H}_{5}}MgCl;\,Y={{(C{{H}_{3}})}_{3}}C-OH\]
Correct Answer: C
Solution :
\[C{{H}_{3}}COC{{H}_{3}}+\underset{\text{(X)}}{\mathop{C{{H}_{3}}MgCl}}\,\to {{(C{{H}_{3}})}_{3}}C-OMgCl\] \[\xrightarrow{\text{hydrolysis}}{{(C{{H}_{3}})}_{3}}\underset{(Y)}{\mathop{C-OH}}\,+Mg(OH)Cl\]
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