A) Secondary alcohol
B) A primary alcohol
C) Phenol
D) Tert-Butyl alcohol
Correct Answer: A
Solution :
\[\underset{\text{Benzaldehyde}}{\mathop{{{C}_{6}}{{H}_{5}}CHO}}\,\underset{{{H}^{+}}/{{H}_{2}}O}{\mathop{\xrightarrow{C{{H}_{3}}MgBr}}}\,\underset{2{}^\circ \text{Alcohol}}{\mathop{{{C}_{6}}{{H}_{5}}CH(OH)C{{H}_{3}}}}\,\]
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