A) Higher aldehydes with ethanal and higher ketones with propanone
B) Primary alcohols with ethanal and secondary alcohols with propanone
C) Ethers with ethanal and alcohols with propanone
D) Secondary alcohols with ethanal and tertiary alcohols with propanone
Correct Answer: D
Solution :
\[C{{H}_{3}}-MgBr+C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-H\xrightarrow{{{H}_{2}}O}\]\[C{{H}_{3}}-\underset{C{{H}_{3}}}{\mathop{\underset{|\,\,\,\,\,\,\,\,}{\mathop{CH}}\,\,}}\,-OH+MgBr(OH)\] \[C{{H}_{3}}MgBr+C{{H}_{3}}-\underset{C{{H}_{3}}\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C=O}}\,}}\,\xrightarrow{{{H}_{2}}O}\] \[\begin{matrix} C{{H}_{3}} \\ {} \\ OH \\ \end{matrix}>C<\begin{matrix} C{{H}_{3}} \\ {} \\ C{{H}_{3}} \\ \end{matrix}+MgBr(OH)\]
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