A) Mesitylene
B) Phorone
C) Glyoxal
D) Mesityl oxide
Correct Answer: B
Solution :
Phoron \[\begin{matrix} C{{H}_{3}} \\ C{{H}_{3}} \\ \end{matrix}>C=O+{{H}_{2}}CH-\overset{\overset{O}{\mathop{||}}\,}{\mathop{C}}\,-CH{{H}_{2}}+O=C<\begin{matrix} C{{H}_{3}} \\ C{{H}_{3}} \\ \end{matrix}\] \[\underset{-2{{H}_{2}}O}{\mathop{\xrightarrow{\text{Dry }HCl}}}\,\]\[\begin{matrix} C{{H}_{3}} \\ C{{H}_{3}} \\ \end{matrix}>\underset{\text{Phoron}}{\mathop{C=CH-\overset{\overset{O}{\mathop{||}}\,}{\mathop{C}}\,-CH}}\,=C\,<\begin{matrix} C{{H}_{3}} \\ C{{H}_{3}} \\ \end{matrix}\]
You need to login to perform this action.
You will be redirected in
3 sec
