A) \[C{{H}_{3}}C{{H}_{2}}CHO\]
B) \[C{{H}_{3}}CHO\]
C) \[HCHO\]
D) \[C{{H}_{3}}COC{{H}_{3}}\]
Correct Answer: B
Solution :
We know that \[\underset{\text{Acetaldehyde}}{\mathop{\overset{\overset{\,\,\,\,\,H}{\mathop{\,\,\,\,\,\,\,|}}\,}{\mathop{C{{H}_{3}}-C=O}}\,}}\,\xrightarrow{+HCN}\underset{\text{Cyanohydrin}}{\mathop{\underset{\underset{\,\,\,CN}{\mathop{\,\,\,|}}\,}{\mathop{\overset{\overset{\,\,\,\,H}{\mathop{\,\,\,\,|}}\,}{\mathop{C{{H}_{3}}-C-OH}}\,}}\,}}\,\xrightarrow{+{{H}_{2}}O}\]\[\underset{\text{Lactic acid}}{\mathop{\underset{\underset{\,\,COOH}{\mathop{\,\,\,|}}\,}{\mathop{\overset{\overset{\,\,\,H}{\mathop{\,\,\,|}}\,}{\mathop{C{{H}_{3}}-C-OH}}\,}}\,}}\,\] Thus Lactic acid is formed.
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