A) Acetone
B) Acetaldehyde
C) Propionaldehyde
D) Formaldehyde
Correct Answer: A
Solution :
Two molecules of acetone condense in presence of dry HCl gas to form mesityl oxide. \[\begin{matrix} C{{H}_{3}} \\ C{{H}_{3}} \\ \end{matrix}>C=O+{{H}_{2}}-CH-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}\underset{-{{H}_{2}}O}{\mathop{\xrightarrow{HCl}}}\,\] \[{{(C{{H}_{3}})}_{2}}\underset{\text{Mesityl oxide}}{\mathop{C=CH.COC{{H}_{3}}}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
