A) Conc. \[{{H}_{2}}S{{O}_{4}}\]
B) Sodium acetate
C) Sodium metal
D) Anhydrous \[ZnC{{l}_{2}}\]
Correct Answer: B
Solution :
\[{{C}_{6}}{{H}_{5}}CHO+{{(C{{H}_{3}}CO)}_{2}}O\xrightarrow{C{{H}_{3}}C{{O}_{2}}Na}\]\[{{C}_{6}}{{H}_{5}}CH=CHC{{O}_{2}}H\] It is Perkin?s reaction.You need to login to perform this action.
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