A) Sodium bisulphite
B) Ammonia
C) Phosphorus pentachloride
D) Phenyl hydrazine
Correct Answer: B
Solution :
\[C{{H}_{3}}-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-H+N{{H}_{3}}\to C{{H}_{3}}-\underset{N{{H}_{2}}\,\,\,\,}{\overset{OH\,\,\,\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,\,\,\,\,}{\overset{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}{\mathop{C-H}}}\,}}}\,\] \[2C{{H}_{3}}-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}+N{{H}_{3}}\to C{{H}_{3}}-\underset{N{{H}_{2}}}{\overset{C{{H}_{3}}\,}{\mathop{\underset{|\,\,\,\,\,\,\,\,\,}{\overset{|\,\,\,\,\,\,\,\,\,}{\mathop{C\,\,-\,}}}\,}}}\,C{{H}_{2}}\overset{O}{\mathop{\overset{|\,|}{\mathop{-C\,\,\,}}\,}}\,-C{{H}_{3}}\]
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