A) Benzyl alcohol and sodium formate
B) Sodium benzoate and methyl alcohol
C) Sodium benzoate and sodium formate
D) Benzyl alcohol and methyl alcohol
Correct Answer: A
Solution :
Crossed aldol reaction gives benzyl alcohol and sodium formate. \[\underset{\text{Benzaldehyde}}{\mathop{{{C}_{6}}{{H}_{5}}CHO}}\,\,+\underset{\text{Formaldehyde}}{\mathop{HCHO}}\,\xrightarrow{NaOH\,(aq)}\]\[\underset{\text{Benzyl}\,\text{alcohol}}{\mathop{{{C}_{6}}{{H}_{5}}C{{H}_{2}}OH}}\,\,+\underset{\text{Sod}\text{.}\,\text{formate}}{\mathop{HCOONa}}\,\]
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