A) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}OH\]
B) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CHO\]
C) \[C{{H}_{3}}-CH=CHCHO\]
D) \[C{{H}_{3}}-CH=CHC{{H}_{2}}OH\]
Correct Answer: C
Solution :
\[C{{H}_{3}}CHO\xrightarrow{dil\,\,NaOH}\underset{\text{Aldol}}{\mathop{C{{H}_{3}}-\underset{OH}{\mathop{\underset{|\,\,\,\,\,}{\mathop{CH}}\,}}\,-C{{H}_{2}}-CHO}}\,\]\[\xrightarrow{Heat}\underset{{}}{\mathop{C{{H}_{3}}-CH=CH-CHO+{{H}_{2}}O}}\,\]
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