A) \[{{C}_{6}}{{H}_{5}}CH=CHCO{{C}_{6}}{{H}_{5}}\]
B) \[{{C}_{6}}{{H}_{5}}COC{{H}_{2}}{{C}_{6}}{{H}_{5}}\]
C) \[{{C}_{6}}{{H}_{5}}CH=CH{{C}_{6}}{{H}_{5}}\]
D) \[{{C}_{6}}{{H}_{5}}CH(OH)CO{{C}_{6}}{{H}_{5}}\]
Correct Answer: A
Solution :
\[{{C}_{6}}{{H}_{5}}CHO+C{{H}_{3}}CO{{C}_{6}}{{H}_{5}}\underset{-{{H}_{2}}O}{\mathop{\xrightarrow{NaOH}}}\,\]\[\underset{\text{Benzyl acetophenone}}{\mathop{{{C}_{6}}{{H}_{5}}-CH=CH-\overset{_{||}^{O}}{\mathop{C}}\,-{{C}_{6}}{{H}_{5}}}}\,\]
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