A) 5
B) -4
C) Either (a) or (b)
D) 6
Correct Answer: A
Solution :
(a): \[x=\text{ }\sqrt{20+x}\] \[{{x}^{2}}-x-20=0\] \[(x-5)(x+4)=0\] \[x=5\] or \[-\,4\] But x must be positive. \[\therefore x=5\]
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