A) \[y=\frac{1}{2}\]
B) \[y=\frac{7}{4}\]
C) \[y=0\]
D) No solution over real numbers
Correct Answer: B
Solution :
(b): Use the formula and check the coefficient of\[{{x}^{2}}\]. \[f(x)={{x}^{2}}-5x+\frac{25}{4}+8-\frac{25}{4}={{\left( x-\frac{5}{2} \right)}^{2}}+\frac{7}{4}\] \[\therefore \]min value \[=\frac{7}{4}\]You need to login to perform this action.
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