A) \[f\left( 0 \right)=a\]
B) \[f\left( a \right)=f\left( 0 \right)\]
C) \[f\left( a \right)=0\]
D) \[~f\left( \pm a \right)=\pm a\]
Correct Answer: A
Solution :
(a): Let the roots be \[\alpha \]and \[\alpha +1\]. \[\alpha +(\alpha +1)=\]p, i.e., \[2\alpha +1=p\] \[(\alpha )(\alpha +1)=\frac{q}{1}=q\]You need to login to perform this action.
You will be redirected in
3 sec