A) \[{{x}^{2}}-4x+3\sqrt{2}=0\]
B) \[{{x}^{2}}+2x-6\sqrt{2}=0\]
C) \[{{x}^{2}}-4x-3\sqrt{2}=0\]
D) \[3{{x}^{2}}-4\sqrt{3x}-4=0\]
Correct Answer: A
Solution :
(a): Aliter: By physical inspection also, one can arrive at the answer: In (B), (C) and (D) ?c? term is negative which make 4ac as positive & hence \[{{b}^{2}}-4ac\]as positive.\[\Rightarrow \](B), (C), (D) cannot be correct options.
You need to login to perform this action.
You will be redirected in
3 sec
