A) \[1,-8\]
B) \[1,-2\]
C) \[\frac{2}{3},\frac{1}{3}\]
D) \[-2,-8\]
Correct Answer: A
Solution :
Given equation is \[{{x}^{2/3}}+{{x}^{1/3}}-2=0\] Let \[y={{x}^{1/3}}\] \[\Rightarrow \] \[{{y}^{2}}+y-2=0\] \[\Rightarrow \]\[{{y}^{2}}+2y-y-2=0\] \[\Rightarrow \]\[(y-1)(y+2)=0\] \[\Rightarrow \]\[y=1\] or \[y=-2\]\[\Rightarrow \] \[{{x}^{1/3}}=1\]or \[{{x}^{1/3}}=-2\] \[\Rightarrow \] \[x=1\] or \[x=-8\]You need to login to perform this action.
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