A) \[\frac{-1}{2},1\]
B) \[-1,\frac{1}{2}\]
C) \[\frac{1}{2},1\]
D) \[-1,\frac{-1}{2}\]
Correct Answer: D
Solution :
\[=\left( \frac{144}{48}+\frac{384}{48}+\frac{240}{48} \right)=3+8+5=16\] \[\frac{a}{b}\] \[\frac{c}{d}=\frac{L.C.M.(a,c)}{H.C.F.(b,d)}\] \[\Rightarrow \] \[L.C.M.\]or \[\frac{6}{14}and\frac{2}{7}\]You need to login to perform this action.
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