A) 1
B) 0
C) 6
D) 16
Correct Answer: A
Solution :
(a): Let, n, n + 1 be roots. \[\therefore 2p=2n+1\] and \[4q={{n}^{2}}+n\]; Now \[D=4{{p}^{2}}-16q={{(2n+1)}^{2}}-4({{n}^{2}}+n)=1\]
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