A) \[a+b+c=0\]
B) \[a+b+c>0\]
C) \[a+b+c<0\]
D) None of these
Correct Answer: A
Solution :
(a): Let \[f(x)=a{{x}^{2}}+bx+c\]. Appreciation of graph will help us solve the problem. Since,\[~\alpha >1\] and \[~\beta >1\], therefore, from figure, we can appreciate that\[f\left( 1 \right)>0\therefore a+b+c>0\].You need to login to perform this action.
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