A) \[m=-6\]
B) \[m=-3\]
C) \[m=-7\]
D) \[m=5\]
Correct Answer: A
Solution :
(a): \[\frac{m-5}{{{m}^{2}}+5m-14}>0\Rightarrow \frac{(m-5)}{(m-2)(m+7)}>0\] Please see the number line below to understand the regions where the above in equation will become positive. Hence the solution is\[m\in (-7,2)\cup (5,\infty )\]You need to login to perform this action.
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