A) \[35{}^\circ \]
B) \[45{}^\circ \]
C) \[55{}^\circ \]
D) \[90{}^\circ \]
Correct Answer: C
Solution :
[c] In the adjoining figure, \[\angle DBC=35{}^\circ \]and \[\angle AED\] its complimentary angle. \[\therefore \] \[\angle AED+\angle DBC=90{}^\circ \]\[\Rightarrow \]\[\angle AED=55{}^\circ \] \[\Rightarrow \] \[\angle AED=90{}^\circ -35{}^\circ =55{}^\circ \] \[\Rightarrow \] \[\angle AED=55{}^\circ \] |
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