A) \[60{}^\circ \]
B) \[75{}^\circ \]
C) \[90{}^\circ \]
D) \[120{}^\circ \]
Correct Answer: B
Solution :
[b] \[\angle BEC=60{}^\circ \] (\[\because \,\,\Delta BEC\] is equilateral.) and \[\angle ECB=60{}^\circ \] and \[\angle DBC=45{}^\circ \] (\[\because \]BD is diagonal.) Now, in \[\because \]\[\Delta \Beta {\mathrm O}C\] \[\angle BOC+\angle OBC+\angle OCB=180{}^\circ \] \[\Rightarrow \] \[\angle BOC+45{}^\circ +60{}^\circ =180{}^\circ \] \[\Rightarrow \] \[\angle BOC=75{}^\circ \] |
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